Exam

JEE Main

Year

2019

Date

12 January

Shift

Evening Shift

Subject

Physics

Chapter

Oscillations

JEE Main 2019 · 12 January · Evening Shift · Physics · Oscillations

A simple harmonic motion is represented by: y = 5( 3 + 3 3 )cm The...

A simple harmonic motion is represented by:
$y = 5\left(\sin 3\pit + \sqrt{3}\cos 3\pit\right)cm$
The amplitude and time period of the motion are:

Step-by-step solution

$y = 5\sin \left(3\pit\right) + 5\sqrt{3}\cos \left(3\pit\right)$



${A}^{2} = {5}^{2} + {\left(5\sqrt{3}\right)}^{2} = {10}^{2}$

$A = 10cm$

$\omega = 3\pi$

$T = \dfrac{2\pi}{\omega} = \dfrac{2}{3}s$