JEE Main201912 Jan 2019Evening ShiftPhysicsOscillationsActual
A simple harmonic motion is represented by: y = 5 sin 3 π t + 3 cos 3 π t cm The amplitude and time period of the motion are:
Options
- A5   cm ,   2 3   s
- B10   cm ,   2 3   s
- C5   cm ,   3 2   s
- D10   cm ,   3 2   s
Correct answer
B. 10   cm ,   2 3   s
Step-by-step solution
y = 5 sin 3 π t + 5 3 cos 3 π t A 2 = 5 2 + 5 3 2 = 10 2 A = 10   cm ω = 3 π T = 2 π ω = 2 3   s