JEE Main201911 Jan 2019Evening ShiftPhysicsOscillationsActual
A simple pendulum of length 1 ~m is oscillating with an angular frequency 10 rad / s . The support of the pendulum starts oscillating up and down with a small angular frequency of 1 rad / s and an amplitude of 10⁻² ~m . The relative change in the angular frequency of the pendulum is best given by :
Options
- A10⁻³ rad / s
- B1 rad / s
- C10⁻¹ rad / s
- D10⁻⁵ rad / s
Correct answer
A. 10⁻³ rad / s
Step-by-step solution
Angular frequency of pendulum = g relative change in angular frequency = 1 2 g g [ as length remains constant ] g=2 ~A _ s ² [ _ s = . angular frequency of support and, A = amplitude] = 1 2 2 ~A _ S ² ~g = 1 2 2 1² 10⁻² 10 =10⁻³ rad / sec