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JEE Main201910 Jan 2019Evening ShiftPhysicsOscillationsActual

A particle executes simple harmonic motion with an amplitude of 5 c m . When the particle is at 4 c m from the mean position, the magnitude of its velocity in S I units is equal to that of its acceleration. Then, its periodic time in seconds is:

Options

  1. A8 π 3
  2. B3 8 π
  3. C4 π 3
  4. D7 3 π

Correct answer

A. 8 π 3

Step-by-step solution

v = ω 5 2 - 4 2 = 3 ω a = ω 2 × 4 a = v 4 ω 2 = 3 ω ω = 3 4 = 2 π T T = 8 π 3 s e c

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