JEE Main20199 Jan 2019Evening ShiftPhysicsOscillationsActual
A particle is executing simple harmonic motion ( S H M ) of amplitude A , along the x -axis, about x = 0 . When its potential Energy P E equal kinetic energy K E , the position of the particle will be:
Options
- AA
- BA 2
- CA 2 2
- DA 2
Correct answer
D. A 2
Step-by-step solution
P E = 1 2 k x 2 &   K E = 1 2 K A 2 - x 2 As given in question K E = P E ⇒ 1 2 K A 2 - x 2 = 1 2 K x 2 ⇒ 2 x 2 = A 2 ⇒ x = ± A 2