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Two particles are performing simple harmonic motion in a straight line about the same equilibrium point. The amplitude and time period for both particles are same and equal to A and T , respectively. At time t = 0 one particle has displacement A while the other one has displacement - A 2 and they are moving towards each other. If they cross each other at time t , then t is:

Options

  1. A5 T 6
  2. BT 3
  3. CT 4
  4. DT 6

Correct answer

D. T 6

Step-by-step solution

Angle covered to meet = 60 o = π 3 r a d Therefore, t = θ ω = π 3 × T 2 π = T 6

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