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JEE Main 201411 AprilOnline
Exam
JEE Main
Year
2014
Date
11 April
Mode
Online
Subject
Physics
Chapter
Oscillations

JEE Main 2014 · 11 April · Online · Physics · Oscillations

The angular frequency of the damped oscillator is given by, ω= ( k...

The angular frequency of the damped oscillator is given by, ω=(km−r24 m2)\omega=\sqrt{\left(\frac{\mathrm{k}}{\mathrm{m}}-\frac{\mathrm{r}^2}{4 \mathrm{~m}^2}\right)}wherewhere\mathrm{k} is the spring constant, m\mathrm{m} is the mass of the oscillator and rr is the damping constant. If the ratio r2mk\frac{r^2}{\mathrm{mk}} is 8%8 \%, the change in time period compared to the undamped oscillator is approximately as follows:

Options

  1. Aincreases by 1%1 \%
  2. Bincreases by 8%8 \%
  3. Cdecreases by 1%1 \%
  4. Ddecreases by 8%8 \%

Correct answer

A. increases by 1%1 \%

Step-by-step solution

The change in time period compared to the undamped oscillator increases by 1%1 \%.
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