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JEE Main 20146 April
Exam
JEE Main
Year
2014
Date
6 April
Subject
Physics
Chapter
Oscillations

JEE Main 2014 · 6 April · Physics · Oscillations

A particle moves with simple harmonic motion in a straight line. In...

A particle moves with simple harmonic motion in a straight line. In first τsτ s, after starting from rest it travels a distance a, and in next τsτ s it travels 2a, in same direction, then :

Options

  1. AAmplitude of motion is 3a
  2. BTime period of oscillations is 8 τ
  3. CAmplitude of motion is 4a
  4. DTime period of oscillations is 6 τ

Correct answer

D. Time period of oscillations is 6 τ

Step-by-step solution

x=−Acosωt\text{x} = - A cos \omega \text{t}

−A+a=−A cosωτ- \text{A} + \text{a} = - \text{A cos} \omega τ ...(i)

−A+3a=−A cos(ω2τ)- \text{A} + 3 \text{a} = - \text{A cos} \left(\omega 2 τ\right) ...(ii)

∴ - 1 + \dfrac{\text{a}}{\text{A}} = - \text\cos \omega τ ...(iii)

and - 1 + \dfrac{3 \text{a}}{\text{A}} = - \text\cos \left(2 \omega τ\right) ...(iv)

Adding (iii) and (iv)

2 = 3 \cos \left(\omega τ\right) - 2 {\text\cos}^{2} \left(\omega τ\right) + 1

∴ 2 {\text\cos}^{2} \left(\omega τ\right) - 3 \text\cos \left(\omega τ\right) + 1 = 0

∴ \text\cos \omega τ = \dfrac{1}{2}

∴ωτ=π3∴ \omega τ = \dfrac{\pi}{3}

∴T=6τ∴ \text{T} = 6 τ

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