JEE Main2007PhysicsOscillationsActual
A point mass oscillates along the x -axis according to the law x=x₀ ( t- / 4) . If the acceleration of the particle is written as a=A ( t+ )
Options
- AA = x ₀, =- / 4
- BA = x ₀ ^2, =- / 4
- CA = x ₀ ^2, =- / 4
- DA=x₀ ^2, =3 / 4
Correct answer
D. A=x₀ ^2, =3 / 4
Step-by-step solution
v=-x₀ ( t- / 4) a=-x₀ ^2 ( t+ - 4 ) a=A ( t+ ) A=x₀ ^2 ; = 3 4