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A particle of mass m executes simple harmonic motion with amplitude ' a ' and frequency ' v '. The average kinetic energy during its motion from the position of equilibrium to the end is

Options

  1. A^2 ma ^2 v^2
  2. B1 4 ^2 m a^2 v^2
  3. C4 ^2 ma ^2 v ^2
  4. D2 ^2 m a^2 v^2

Correct answer

A. ^2 ma ^2 v^2

Step-by-step solution

1 4 m a^2 ^2= ^2 f^2 m a^2

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