JEE Main2005PhysicsOscillationsActual
Two simple harmonic motions are represented by the equation y ₁=0.1 (100 t+ 3 ) and y₂=0.1 t . The phase difference of the velocity of particle 1 w.r.t. the velocity of the particle 2 is
Options
- A- / 6
- B/ 3
- C- / 3
- D/ 6
Correct answer
A. - / 6
Step-by-step solution
Phase difference ( )=99 t + / 3- / 2 at t=0, =- / 6 .