JEE Main2004PhysicsOscillationsActual
A particle at the end of a spring executes simple harmonic motion with a period t₁ , while the corresponding period for another spring is t₂ . If the period of oscillation with the two springs in series is t , then
Options
- AT = t ₁+ t ₂
- Bx ^2
- CT ⁻¹= t ₁⁻¹+ t ₂⁻¹
- DT ⁻²= t ₁^2+ t ₂^2
Correct answer
B. x ^2
Step-by-step solution
t₁^2+t₂^2=T^2