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JEE Main2003PhysicsOscillationsActual

A mass M is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes SHM of time period T. If the mass is increased by m , the time period becomes 5 ~T 3 . Then the ratio of m M is

Options

  1. A3 5
  2. B25 9
  3. C16 9
  4. D5 3

Correct answer

C. 16 9

Step-by-step solution

T =2 M K 5 ~T 3 =2 M + m K Dividing equation (ii) by equation (i), 5 3 = M + m M . Squaring both the sides 25 9 = M+m M =1+ m M m M = 25 9 -1= 16 9

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