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JEE Main 20258 AprilEvening Shift
Exam
JEE Main
Year
2025
Date
8 April
Shift
Evening Shift
Subject
Physics
Chapter
Ray Optics

JEE Main 2025 · 8 April · Evening Shift · Physics · Ray Optics

A convex lens of focal length 30 cm is placed in contact with a...

A convex lens of focal length 30 cm is placed in contact with a concave lens of focal length 20 cm. An object is placed at 20 cm to the left of this lens system. The distance of the image from the lens in cm is ________

Options

  1. A30
  2. B45
  3. C607\frac{60}{7}
  4. D15

Correct answer

D. 15

Step-by-step solution

Equivalent focal length
<br/>1f=1f1+1f2=130+1−20=2−360=−160f=−60 cm<br/>\begin{aligned}<br/>& \frac{1}{f}=\frac{1}{f_1}+\frac{1}{f_2} \\ & =\frac{1}{30}+\frac{1}{-20}=\frac{2-3}{60}=-\frac{1}{60} \\ & f=-60 \mathrm{~cm}<br/>\end{aligned}
Lens formula
<br/>1v−1u=1f1v−1−20=1−60v=−15 cm<br/>\begin{aligned}<br/>& \frac{1}{\mathrm{v}}-\frac{1}{\mathrm{u}}=\frac{1}{\mathrm{f}} \\ & \frac{1}{\mathrm{v}}-\frac{1}{-20}=\frac{1}{-60} \\ & \mathrm{v}=-15 \mathrm{~cm}<br/>\end{aligned}
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