JEE Main202523 Jan 2025Morning ShiftPhysicsRay OpticsActual
A spherical surface of radius of curvature R , separates air from glass (refractive index =1.5 ). The centre of curvature is in the glass medium. A point object ' O ' placed in air on the optic axis of the surface, so that its real image is formed at ' I ' inside glass. The line OI intersects the spherical surface at P and PO = PI . The distance PO equals to
Options
- A5 R
- B3 R
- C1.5 R
- D2 R
Correct answer
A. 5 R
Step-by-step solution
aligned & PO = u =- x & PI = v = x & PO = PI & ₂ v - ₁ u = ₂- ₁ R & 1.5 x + 1 x = 1 2 R & 5 2 x = 1 2 R & X =5 R aligned