JEE Main202523 Jan 2025Morning ShiftPhysicsRay OpticsActual
Given a thin convex lens (refractive index ₂ ), kept in a liquid (refractive index ₁, ₁ ₂ ) having radii of curvatures |R₁ | and |R₂ | . Its second surface is silver polished. Where should an object be placed on the optic axis so that a real and inverted image is formed at the same place?
Options
- A₁ | R ₁ | | R ₂ | ₂ ( | R ₁ |+ | R ₂ | )- ₁ | R ₂ |
- B₁ | R ₁ | | R ₂ | ₂ ( | R ₁ |+ | R ₂ | )- ₁ | R ₁ |
- C( ₂+ ₁ ) | R ₁ | ( ₂- ₁ )
- D₁ | R ₁ | | R ₂ | ₂ (2 | R ₁ |+ | R ₂ | )- ₁ | R ₁ | | R ₂ |
Correct answer
A. ₁ | R ₁ | | R ₂ | ₂ ( | R ₁ |+ | R ₂ | )- ₁ | R ₂ |
Step-by-step solution
aligned & 1 f _ eq = 2 f _ L - 1 f _ m & f _ m =- | R ₂ | 2 & 1 f _ L = ( ₂ ₁ -1 ) ( 1 R ₁ + 1 R ₂ ) aligned aligned & 1 f _ eq =2 ( ₂- ₁ ₁ ) ( R ₁+ R ₂ R ₁ R ₂ )+ 2 R ₂ & = 2 R ₂ [ ( ₂- ₁ ) ( R ₁+ R ₂ )+ ₁ R ₁ ₁ R ₁ ] & = 2 R ₂ [ ₂ R ₁+ ₂ R ₂- ₁ R ₁- ₁ R ₂+ ₁ R ₁ ₁ R ₁ ] & 1 f _ eq = 2 [ ₂ R ₁+ ₂ R ₂- ₁ R ₂ ] ₁ R ₁ R ₂ aligned For same size of image aligned & u =2 f & u = ₁ R ₁ R ₂ ₂ R ₁+ ₂ R ₂- ₁ R ₂ aligned