A microscope is focused on an object at the bottom of a bucket. If liquid with refractive index (5)/(3) is poured inside the bucket, then microscope have to be raised by 30cm to focus the object again. The height of the

Correct answer: A. 75cm In this case shift is given by,& shift= d(1 - (1)/(μ)) = 30cm ⇒ d[1 - (1)/(53)] = 30 ⇒ d = (30 × 5)/(2) = 75cm

JEE Main 202331 JanuaryEvening Shift

JEE Main 2023 · 31 January · Evening Shift · Physics · Ray Optics

A microscope is focused on an object at the bottom of a bucket. If...

A microscope is focused on an object at the bottom of a bucket. If liquid with refractive index

\dfrac{5}{3}

is poured inside the bucket, then microscope have to be raised by

30cm

to focus the object again. The height of the liquid in the bucket is :

A. $75cm$

In this case shift is given by,& $\text{shift}= d\left(1 - \dfrac{1}{μ}\right) = 30cm$

$⇒ d\left[1 - \dfrac{1}{53}\right] = 30$

$⇒ d = \dfrac{30 \times 5}{2} = 75cm$