JEE Main20266 April 2026Morning ShiftPhysicsRotational MotionActual
A solid sphere of radius 4 cm and mass 5 kg is rotating (rotation axis is passing through the centre of the sphere) with an angular velocity of 1200 rpm. It is brought to rest in 10 s by applying a constant torque. The torque applied and the number of rotations it made before it comes to rest are _______ and _______ respectively.
Options
- A0.128 Nm, 100
- B0.0128 Nm, 50
- C0.128 Nm, 50
- D0.0128 Nm, 100
Correct answer
D. 0.0128 Nm, 100
Step-by-step solution
Initial angular velocity ₀ = 1200 rpm = 1200 2 60 = 40 rad/s Final angular velocity = 0 Time t = 10 s Angular acceleration = - ₀ t = 0 - 40 10 = -4 rad/s ^2 Moment of inertia of the solid sphere I = 2 5 MR^2 = 2 5 5 (0.04)^2 = 0.0032 kg m ^2 Torque = I| | = 0.0032 4 = 0.0128 Nm Angle rotated = ₀ + 2 t = 40 + 0 2 10 = 200 rad Number of rotations N = 2 = 200 2 = 100 Answer: 0.0128 Nm, 100