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JEE Main 202624 JanuaryMorning Shift
Exam
JEE Main
Year
2026
Date
24 January
Shift
Morning Shift
Subject
Physics
Chapter
Thermal Properties of Matter

JEE Main 2026 · 24 January · Morning Shift · Physics · Thermal Properties of Matter

A brass wire of length 2 m and radius 1 mm at 27^ C is held taut...

A brass wire of length 2 m and radius 1 mm at 27∘C27^{\circ} \mathrm{C} is held taut between two rigid supports. Initially it was cooled to a temperature of −43∘C-43^{\circ} \mathrm{C} creating a tension TT in the wire. The temperature to which the wire has to be cooled in order to increase the tension in it to 1.4T1.4 T, is ____\_\_\_\_ ∘C{ }^{\circ} \mathrm{C}.

Options

  1. A-86
  2. B-65
  3. C-71
  4. D-80

Correct answer

C. -71

Step-by-step solution

Thermal stress in the wire is caused by contraction.
At -43°C, the temperature drop from 27°C is ΔT1=70°C\Delta T_1 = 70°C
It creates tension T=YAαΔT1T = YA\alpha\Delta T_1 where YY is Young's modulus and α\alpha is linear expansion coefficient.
For tension to increase to 1.4T1.4T, the new temperature drop must be: ΔT2=1.4×70=98°C\Delta T_2 = 1.4 \times 70 = 98°C.
Required temperature: T3=27−98=−71°CT_3 = 27 - 98 = -71°C
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