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JEE Main 202624 JanuaryEvening Shift
Exam
JEE Main
Year
2026
Date
24 January
Shift
Evening Shift
Subject
Physics
Chapter
Wave Optics

JEE Main 2026 · 24 January · Evening Shift · Physics · Wave Optics

In the Young's double slit experiment the intensity produced by...

In the Young's double slit experiment the intensity produced by each one of the individual slits is I0I_{0}. The distance between two slits is 2 mm. The distance of screen from slits is 10 m. The wavelength of light is 6000 A∘6000 \mathrm{~A}^{\circ}. The intensity of light on the screen in front of one of the slits is ____\_\_\_\_.

Options

  1. AIo2\frac{I_{\mathrm{o}}}{2}
  2. B2Io2 I_{\mathrm{o}}
  3. C4Io4 I_{\mathrm{o}}
  4. DIoI_{\mathrm{o}}

Correct answer

D. IoI_{\mathrm{o}}

Step-by-step solution

In Young's double slit experiment:
d=2d = 2 mm, D=10D = 10 m, λ=6000\lambda = 6000 Å
The point in front of one slit is at y=d2y = \frac{d}{2} from the central axis.
I=4I0cos⁡2(πdyλD)I = 4I_0 \cos^2\left(\frac{\pi d y}{\lambda D}\right)
=4I0cos⁡2(π×2×10−3×1×10−36000×10−10×10)= 4I_0 \cos^2\left(\frac{\pi \times 2 \times 10^{-3} \times 1 \times 10^{-3}}{6000 \times 10^{-10} \times 10}\right)
=4I0cos⁡2(π3)=4I0×14=I0= 4I_0 \cos^2\left(\frac{\pi}{3}\right) = 4I_0 \times \frac{1}{4} = I_0
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