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JEE Main20249 Apr 2024Morning ShiftPhysicsWave OpticsActual

In a Young's double slit experiment, the intensity at a point is ( 1 4 )^ th of the maximum intensity, the minimum distance of the point from the central maximum is ________ m . (Given : =600 ~nm , ~d =1.0 ~mm , D =1.0 ~m )

Correct answer

0

Step-by-step solution

aligned & I = I ₀ ^2 ( 2 ) & I ₀ 4 = ^2 ( 2 ) & = 2 3 & 2 ( yd D )= 2 3 & y = D 3 ~d = 600 10⁻⁹ 1 3 10⁻³ =2 10⁻⁴ ~m aligned

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