Two slits are 1 ~mm apart and the screen is located 1 ~m away from the slits. A light of wavelength 500 ~nm is used. The width of each slit to obtain 10 maxima of the double slit pattern within the central maximum of

Correct answer: 0 aligned & d=1 ~mm, D=1 ~m, λ=500 ~nm & 10( λ D d )= 2 λ D a & a= d 5 &= 10 × 10^ -4 ~m 5 &=2 × 10^ -4 aligned

JEE Main 20248 AprilEvening Shift

JEE Main 2024 · 8 April · Evening Shift · Physics · Wave Optics

Two slits are 1 ~mm apart and the screen is located 1 ~m away from...

Two slits are

1 \mathrm{~mm}

apart and the screen is located

1 \mathrm{~m}

away from the slits. A light of wavelength

500 \mathrm{~nm}

is used. The width of each slit to obtain 10 maxima of the double slit pattern within the central maximum of the single slit pattern is _____

\times 10^{-4} \mathrm{~m}

\begin{aligned} & \mathrm{d}=1 \mathrm{~mm}, \mathrm{D}=1 \mathrm{~m}, \lambda=500 \mathrm{~nm} \\ & 10\left(\frac{\lambda \mathrm{D}}{\mathrm{d}}\right)=\frac{2 \lambda \mathrm{D}}{\mathrm{a}} \\ & \mathbf{a}=\frac{\mathrm{d}}{5} \\ &=\frac{10 \times 10^{-4} \mathrm{~m}}{5} \\ &=2 \times 10^{-4}\end{aligned}