In Young's double slit experiment, carried out with light of wavelength 5000 , the distance between the slits is 0.3 ~mm and the screen is at 200 ~cm from the slits. The central maximum is at x=0 ~cm . The value of x

Correct answer: 0 β= λ D d = 5 × 10^ -7 × 2 3 × 10^ -4 = 10 × 10^ -3 3 ~m For 3^ rd maxima y_3=3 β=10 × 10^ -3 ~m= 10 ~mm

JEE Main 20245 AprilMorning Shift

JEE Main 2024 · 5 April · Morning Shift · Physics · Wave Optics

In Young's double slit experiment, carried out with light of...

In Young's double slit experiment, carried out with light of wavelength

5000 \AA

, the distance between the slits is

0.3 \mathrm{~mm}

and the screen is at

200 \mathrm{~cm}

from the slits. The central maximum is at

x=0 \mathrm{~cm}

. The value of

x

for third maxima is _____

\mathrm{mm}

\beta=\frac{\lambda \mathrm{D}}{\mathrm{d}}=\frac{5 \times 10^{-7} \times 2}{3 \times 10^{-4}}=\frac{10 \times 10^{-3}}{3}

\mathrm{~m}

For

3^{

\text{rd }

}

maxima

y_3=3 \beta=10 \times 10^{-3}

\mathrm{~m}=

\mathrm{~mm}