Two wavelengths λ_1 and λ_2 are used in Young's double slit experiment. λ_1=450 ~nm and λ_2=650 ~nm . The minimum order of fringe produced by λ_2 which overlaps with the fringe produced by λ_1 is n . The value of n is

Correct answer: 0 aligned & n_2 λ_2=n_1 λ_1 & n_2 n_1 =(λ_1)/(λ_2)=(450)/(650)=(9)/(13) & n_2=9 aligned

JEE Main 20244 AprilMorning Shift

JEE Main 2024 · 4 April · Morning Shift · Physics · Wave Optics

Two wavelengths λ_1 and λ_2 are used in Young's double slit...

Two wavelengths

\lambda_1

and

\lambda_2

are used in Young's double slit experiment.

\lambda_1=450 \mathrm{~nm}

and

\lambda_2=650 \mathrm{~nm}

. The minimum order of fringe produced by

\lambda_2

which overlaps with the fringe produced by

\lambda_1

n

. The value of

n

is _____.

\begin{aligned} & \mathrm{n}_2 \lambda_2=\mathrm{n}_1 \lambda_1 \\ & \frac{\mathrm{n}_2}{\mathrm{n}_1}=\frac{\lambda_1}{\lambda_2}=\frac{450}{650}=\frac{9}{13} \\ & \mathrm{n}_2=9\end{aligned}