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In a Young’s double slit experiment, the ratio of amplitude of light coming from slits is 2 : 1 . The ratio of the maximum to minimum intensity in the interference pattern is

Options

  1. A9   :   4
  2. B25   :   9
  3. C2   :   1
  4. D9   :   1

Correct answer

D. 9   :   1

Step-by-step solution

The ratio of the maximum to minimum intensity is given by I max I min = I 1 + I 2 2 I 1 - I 2 2 It is given that A 1 A 2 = 2 1 I m a x I m i n = A 1 + A 2 A 1 - A 2 2 = A 2 2 2 + 1 2 A 2 2 ( 2 - 1 ) 2 = 2 + 1 2 - 1 2 = 9 1

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