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JEE Main 202310 AprilEvening Shift
Exam
JEE Main
Year
2023
Date
10 April
Shift
Evening Shift
Subject
Physics
Chapter
Wave Optics

JEE Main 2023 · 10 April · Evening Shift · Physics · Wave Optics

The ratio of intensities at two points P and Q on the screen in a...

The ratio of intensities at two points PP and QQ on the screen in a Young's double slit experiment where phase difference between two waves of same amplitude are π3\dfrac{\pi}{3} and π2\dfrac{\pi}{2}, respectively are

Options

  1. A2:32: 3
  2. B1:31: 3
  3. C3:13: 1
  4. D3:23: 2

Correct answer

D. 3:23: 2

Step-by-step solution

The formula to calculate the intensity of the interference pattern in Young's double slit experiment can be written as

I=4I0cos⁡2(ϕ2)...(1)I = 4{I}_{0}\cos^{2}\left(\dfrac{ϕ}{2}\right) . . . \left(1\right)

Hence, the ratio of the required intensities can be calculated as follows-

{I1I2=4I0cos⁡2(π6)4I0cos⁡2(π4)=3412=32\begin{cases}\dfrac{{I}_{1}}{{I}_{2}} & = & \dfrac{4{I}_{0}\cos^{2}\left(\dfrac{\pi}{6}\right)}{4{I}_{0}\cos^{2}\left(\dfrac{\pi}{4}\right)} \\ & = & \dfrac{\dfrac{3}{4}}{\dfrac{1}{2}} \\ & = & \dfrac{3}{2}\end{cases}

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