In a Young's double slit experiment, the slits are separated by 0 . 3   mm and the screen is 1 . 5   m away from the plane of slits. Distance between fourth bright fringes on both sides of central bright fringe is 2 . 4   cm . The frequency of light used is x × 10 14   Hz .

Step-by-step solution

The distance between n th bright fringe on both side of central maxima is 2 . 4   cm . The f = ? Δ y = D λ d × 8 λ = d Δ y 8 D = 0 . 3 × 10 - 3 × 2 . 4 × 10 - 2 8 × 1 . 5 = 0 . 12 × 10 - 5 2 = 0 . 06 × 10 - 5 λ = 6 × 10 - 7   m f = C 6 × 10 - 7 = 0 . 5 × 10 + 15 f = 5 × 10 14   Hz So, x = 5