In a double – slit experiment, at a certain point on the screen the path difference between the two interfering waves is 1 8 t h of a wavelength. The ratio of the intensity of light at that point to that at the center of a bright frin

Question

In a double &ndash; slit experiment, at a certain point on the screen the path difference between the two interfering waves is 1 8 t h of a wavelength. The ratio of the intensity of light at that point to that at the center of a bright fringe is:

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Correct answer: A. 0.853

I = I 0 c o s 2 &#8710; &#981; 2 I I 0 = c o s 2 2 &#960; &#955; &#215; &#8710; X 2 = c o s 2 &#960; 8 ; I I 0 = 0.853

In a double – slit experiment, at a certain point on the screen the path difference between the two interfering waves is 1 8 t h of a wavelength. The ratio of the intensity of light at that point to that at the center of a bright fringe is:

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Correct answer

Step-by-step solution

More from Wave Optics

In a double &ndash; slit experiment, at a certain point on the screen the path difference between the two interfering waves is 1 8 t h of a wavelength. The ratio of the intensity of light at that point to that at the center of a bright fringe is:

Options

Correct answer

Step-by-step solution

More from Wave Optics

In a double – slit experiment, at a certain point on the screen the path difference between the two interfering waves is 1 8 t h of a wavelength. The ratio of the intensity of light at that point to that at the center of a bright fringe is: