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JEE Main20207 Jan 2020Evening ShiftPhysicsWave OpticsActual

In a Young’s double slit experiment, the separation between the slits is 0.15 m m . In the experiment, a source of light of wavelength 589 n m is used and the interference pattern is observed on a screen kept 1.5 m away. The separation between the successive bright fringes on the screen is:

Options

  1. A6.9 m m
  2. B3.9 m m
  3. C5.9 m m
  4. D4.9 m m

Correct answer

C. 5.9 m m

Step-by-step solution

β = λ D d = 589 × 10 - 9 × 1.5 0.15 × 10 - 3 = 5.9 m m

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