Visible light of wavelength 6000 × 10 - 8 c m falls normally on a single slit and produces a diffraction pattern. It is found that the second diffraction minimum is at 60 o from the central maximum. If the first minimum is produced at θ 1 , then θ 1 is close to

Step-by-step solution

For 2 n d minima, d sin ⁡ θ = 2 λ sin ⁡ θ = 3 2 , (given) ⇒ λ d = 3 4 ...(1) So, for 1 s t minima d s i n θ = λ ⇒ sin θ = λ d = 3 4 ⇒ θ = 25.65 o ⇒ θ ≈ 25 o