A polarizer - analyser set is adjusted such that the intensity of...

A polarizer - analyser set is adjusted such that the intensity of light coming out of the analyser is just

36%

of the original intensity. Assuming that the polarizer - analyser set does not absorb any light, the angle by which the analyser needs to be rotated further, to reduce the output intensity to zero, is $\left(\sin^{- 1}\left(\dfrac{3}{5}\right) = 37 °\right)

Options

A ${53}^{o}$
B ${37}^{o}$
C ${90}^{o}$
D ${45}^{o}$

Correct answer

B. ${37}^{o}$

Step-by-step solution

$I = {I}_{0}co{s}^{2}\theta$
$0 . 36{I}_{0} = {I}_{0}\cos^{2}\theta$
$\cos \left(\theta\right) = \dfrac{3}{5}$

$⇒ \theta = 53 °$

angle rotated should be $= {90}^{o} - {53}^{o} = {37}^{o}$

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