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JEE Main201910 Apr 2019Evening ShiftPhysicsWave OpticsActual

In a Young's double-slit experiment, the ratio of the slit's width is 4 : 1 . The ratio of the intensity of maxima to minima, close to the central fringe on the screen, will be

Options

  1. A25 : 9
  2. B9 : 1
  3. C3 + 1 4 : 16
  4. D4 : 1

Correct answer

B. 9 : 1

Step-by-step solution

I n t e n s i t y   ∝   w i d t h   o f   s l i t I 1 I 2 = 4 1 . I m a x I m i n = I 1 + I 2 I 1 - I 2 2 = I 1 I 2 + 1 I 1 I 2 - 1 2   = 4 + 1 4 - 1 2 = 3 1 2 = 9 1 I m a x   : I m i n = 9 : 1

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