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JEE Main 20199 AprilMorning Shift
Exam
JEE Main
Year
2019
Date
9 April
Shift
Morning Shift
Subject
Physics
Chapter
Wave Optics

JEE Main 2019 · 9 April · Morning Shift · Physics · Wave Optics

The figure shows a Young's double slit experimental setup. It is...

The figure shows a Young's double slit experimental setup. It is observed that when a thin transparent sheet of thickness t and refractive index μ\mu is put in front of one of the slits, the central maximum gets shifted by a distance equal to n fringe width. If the wavelength of light used is λ\lambda then tt will be:
The figure shows a Young's double slit experimental setup. It is observed that when a thin transparent sheet of

Options

  1. ADλa(μ−1)\dfrac{D\lambda}{a ( \mu - 1 )}
  2. Bnλ(μ−1)\dfrac{n\lambda}{( \mu - 1 )}
  3. C2nλ(μ−1)\dfrac{2n\lambda}{( \mu - 1 )}
  4. D2Dλa(μ−1)\dfrac{2D\lambda}{a ( \mu - 1 )}

Correct answer

B. nλ(μ−1)\dfrac{n\lambda}{( \mu - 1 )}

Step-by-step solution

Shift in central maxima =Da(μ−1)t<br/>Fringewidth= \dfrac{D}{a}\left(\mu - 1\right)t <br/>Fringe width= \dfrac{D\lambda}{a}
It's given,
Da(μ−1)t=nDλa\dfrac{D}{a}\left(\mu - 1\right)t = n\dfrac{D\lambda}{a}
t=nλμ−1t = \dfrac{n\lambda}{\mu - 1}
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