JEE Main20198 Apr 2019Morning ShiftPhysicsWave OpticsActual
In an interference experiment the ratio of amplitudes of coherent waves is a 1 a 2 = 1 3 . The ratio of maximum and minimum intensities of fringes will be:
Options
- A4
- B9
- C2
- D18
Correct answer
A. 4
Step-by-step solution
I m a x I m i n = a 1 + a 2 a 1 - a 2 2 = a 1 / a 2 + 1 a 1 / a 2 - 1 2 = 1 3 + 1 1 3 - 1 2 I m a x : I m i n = 4 : 1