JEE Main2012PhysicsWave OpticsActual
The first diffraction minimum due to the single slit diffraction is seen at =30^ for a light of wavelength 5000 Å falling perpendicularly on the slit. The width of the slit is
Options
- A2.5 10⁻⁵ ~cm
- B1.25 10⁻⁵ ~cm
- C10 10⁻⁵ ~cm
- D5 10⁻⁵ ~cm
Correct answer
C. 10 10⁻⁵ ~cm
Step-by-step solution
For first minimum, d = aligned d & = = 5000 10⁻⁸ ~cm 30^ & = 5000 10⁻⁸ ~cm 1 / 2 =10 10⁻⁵ ~cm aligned