In a Young's double slit experiment with light of wavelength λ , fringe pattern on the screen has fringe width β . When two thin transparent glass (refractive index μ ) plates of thickness t_1 and t_2 (t_1>t_2) are

Correct answer: C. (β(μ-1)/(λ)(t_1-t_2. aligned Shift & =(β(μ-1))/(λ) t_1-(β(μ-1))/(λ) t_2 & =(β(μ-1))/(λ)( t_1-t_2) aligned

JEE Main 20127 MayOnline

JEE Main 2012 · 7 May · Online · Physics · Wave Optics

In a Young's double slit experiment with light of wavelength λ ,...

In a Young's double slit experiment with light of wavelength

\lambda

, fringe pattern on the screen has fringe width

\beta

. When two thin transparent glass (refractive index

\mu

) plates of thickness

t_1 and t_2 \left(t_1>t_2\right) are placed in the path of the two beams respectively, the fringe pattern will shift by a distance

C. $\frac{\beta(\mu-1}{\lambda}\left(t_1-t_2\right.$

\begin{aligned}\text{ Shift }& =\frac{\beta(\mu-1)}{\lambda} t_1-\frac{\beta(\mu-1)}{\lambda} t_2 \\ & =\frac{\beta(\mu-1)}{\lambda}\left( t_1-t_2\right) \end{aligned}