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JEE Main 20238 AprilEvening Shift
Exam
JEE Main
Year
2023
Date
8 April
Shift
Evening Shift
Subject
Physics
Chapter
Waves and Sound

JEE Main 2023 · 8 April · Evening Shift · Physics · Waves and Sound

A guitar string of length 90cm vibrates with a fundamental...

A guitar string of length 90cm90cm vibrates with a fundamental frequency of 120Hz120Hz. The length of the string producing a fundamental of 180Hz180Hz will be _____ cmcm

Correct answer

0

Step-by-step solution

The formula to calculate the fundamental frequency produced in a vibrating string is given by

f0=v2L...(1){f}_{0} = \dfrac{v}{2L} . . . \left(1\right)

For the first case, it can be written that

120=v2(90)...(2)120 = \dfrac{v}{2 ( 90 )} . . . \left(2\right)

Similarly, for the second case, it can be written that

180=v2(L)...(3)180 = \dfrac{v}{2 ( L )} . . . \left(3\right)

Divide equation (3) by equation (2) and solve to obtain the required length of the string.

{180120=v2(L)v2(90)=90L⇒L=90×120180=60\begin{cases}\dfrac{180}{120} & = & \dfrac{\dfrac{v}{2\left(L\right)}}{\dfrac{v}{2\left(90\right)}} \\ & = & \dfrac{90}{L} \\ & ⇒ & L = 90 \times \dfrac{120}{180} \\ & = & 60\end{cases}

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