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JEE Main 20238 AprilMorning Shift
Exam
JEE Main
Year
2023
Date
8 April
Shift
Morning Shift
Subject
Physics
Chapter
Waves and Sound

JEE Main 2023 · 8 April · Morning Shift · Physics · Waves and Sound

The engine of a train moving with speed 10m s ^ - 1 towards a...

The engine of a train moving with speed 10ms−110m{s}^{- 1} towards a platform sounds a whistle at frequency 400Hz400Hz. The frequency heard by a passenger inside the train is: (Neglect air speed. Speed of sound in air =330ms−1= 330m{s}^{- 1})

Options

  1. A400Hz400Hz
  2. B200Hz200Hz
  3. C412Hz412Hz
  4. D388Hz388Hz

Correct answer

A. 400Hz400Hz

Step-by-step solution

The formula to calculate the frequency of the sound as heard by the passenger inside the train can be written as

f′=f0[v−vOv−vs]...(1)f ' = {f}_{0}\left[\dfrac{v - {v}_{O}}{v - {v}_{s}}\right] . . . \left(1\right)

Since the passenger is inside the train, the speeds of the source and the observer are the same.

Substitute the values of the known parameters into equation (1) to get the required frequency.

{f′=400[330−10330−10]Hz=400Hz\begin{cases}f ' & = & 400\left[\dfrac{330 - 10}{330 - 10}\right]Hz \\ & = & 400Hz\end{cases}

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