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JEE Main 20238 AprilMorning Shift
Exam
JEE Main
Year
2023
Date
8 April
Shift
Morning Shift
Subject
Physics
Chapter
Waves and Sound

JEE Main 2023 · 8 April · Morning Shift · Physics · Waves and Sound

An organ pipe 40cm long is open at both ends. The speed of sound in...

An organ pipe 40cm40cm long is open at both ends. The speed of sound in air is 360ms−1360m{s}^{- 1}. The frequency of the second harmonic is _________Hz .

Correct answer

900

Step-by-step solution

The formula for the frequency in an open organ pipe is

f=nv2Lf = \dfrac{nv}{2L}

Since, it is a second harmonic, n=2n = 2

The frequency of the second harmonic becomes f=2v2L=vLf = \dfrac{2v}{2L} = \dfrac{v}{L}

The data given is

L=0.4mv=360ms−1L = 0 . 4mv = 360m{s}^{- 1}

Substituting the values in the frequency formula

f=360ms−10.4m=900Hzf = \dfrac{360m{s}^{- 1}}{0 . 4m} = 900Hz

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