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An organ pipe 40   cm long is open at both ends. The speed of sound in air is 360   m   s - 1 . The frequency of the second harmonic is _ _ _ _ _ _ _ _ _   Hz .

Correct answer

900

Step-by-step solution

The formula for the frequency in an open organ pipe is f = n v 2 L Since, it is a second harmonic, n = 2 The frequency of the second harmonic becomes f = 2 v 2 L = v L The data given is L = 0 . 4   m v = 360   m   s - 1 Substituting the values in the frequency formula f = 360   m   s - 1 0 . 4   m = 900   Hz

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