A transverse wave is represented by y = 2 ( - kx)cm . The value of...

The given equation is $y = 2\sin \left(\omegat - kx\right)$

The maximum particle velocity $= A\omega$

And the wave velocity $= \dfrac{\omega}{k}$

For wave velocity to be equal to maximum particle velocity

$\dfrac{\omega}{k} = A\omega$

$⇒ k = \dfrac{1}{A}$

Since, $k = \dfrac{2\pi}{\lambda}$

$\lambda = 2\piA = 4\picm$.