The first overtone frequency of an open organ pipe is equal to the fundamental frequency of a closed organ pipe. If the length of the closed organ pipe is 20 cm . The length of the open organ pipe is _____ cm

Step-by-step solution

The fundamental frequency of the closed organ pipe is given by, f 0 = v 4 l c . The frequency of the first overtone of a open organ pipe is given by, f 1 = 2 × v 2 l o . Since, f 0 = f 1 ⇒ v 4 l c = v l o ⇒ l o = 4 × 20 = 80   cm .