A source and a detector move away from each other in absence of wind with a speed of 20m s ^ - 1 , with respect to the ground. If the detector detects a frequency of 1800Hz of the sound coming from the source, then the

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The formula of apparent frequency in terms of velocity of the source and observer is,& $f^{′} = f \left(\dfrac{v - {v}_{0}}{v + {v}_{s}}\right), now put$ the values which are given in the question,

⇒ 1800 = f\left[\dfrac{340 - 20}{340 + 20}\right] $⇒ f =$ \dfrac{1800 \times 360}{320} $Hz⇒ f = 2025Hz$

A source and a detector move away from each other in absence of...

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