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JEE Main 202120 JulyEvening Shift
Exam
JEE Main
Year
2021
Date
20 July
Shift
Evening Shift
Subject
Physics
Chapter
Waves and Sound

JEE Main 2021 · 20 July · Evening Shift · Physics · Waves and Sound

With what speed should a galaxy move outward with respect to earth...

With what speed should a galaxy move outward with respect to earth so that the sodium-DD line at wavelength 5890A∘5890\overset{∘}{A} is observed at 5896A∘?5896\overset{∘}{A} ?

Options

  1. A306kmsec−1306km{sec}^{- 1}
  2. B322kmsec−1322km{sec}^{- 1}
  3. C296kmsec−1296km{sec}^{- 1}
  4. D336kmsec−1336km{sec}^{- 1}

Correct answer

A. 306kmsec−1306km{sec}^{- 1}

Step-by-step solution

f = {f}_{0}\sqrt{\dfrac{1 + \beta}{1 - \beta}}; \beta = \dfrac{v}{c}</p><p></p><p>\dfrac{f}{{f}_{0}}\sqrt{\dfrac{1 + \beta}{1 - \beta}}</p><p></p><p>{\left(1 + \dfrac{\Deltaf}{{f}_{0}}\right)}^{2} = \left(1 + \beta\right) ( 1 - \beta{)}^{- 1}</p><p></p><p>\betaissmallcomparedtois small compared to1</p><p>(1+2\Deltaff0)=(1+2β)</p><p>\left(1 + \dfrac{2\Deltaf}{{f}_{0}}\right) = \left(1 + 2\beta\right)

β=\Deltaff0=vc\beta = \dfrac{\Deltaf}{{f}_{0}} = \dfrac{v}{c}

v=6×c5890=305.6kmsec−1v = 6 \times \dfrac{c}{5890} = 305 . 6km{sec}^{- 1}

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