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JEE Main 202120 JulyMorning Shift
Exam
JEE Main
Year
2021
Date
20 July
Shift
Morning Shift
Subject
Physics
Chapter
Waves and Sound

JEE Main 2021 · 20 July · Morning Shift · Physics · Waves and Sound

The amplitude of wave disturbance propagating in the positive x...

The amplitude of wave disturbance propagating in the positive xx-direction is given by y=1(1+x)2y = \dfrac{1}{( 1 + x{)}^{2}} at time t=0t = 0 and y=11+(x−2)2y = \dfrac{1}{1 + ( x - 2{)}^{2}} at t=1st = 1s, where xx and yy are in metres. The shape of wave does not change during the propagation. The velocity of the wave will be ms−1.m{s}^{- 1} .

Correct answer

2

Step-by-step solution

At t=0,y=11+x2t = 0, y = \dfrac{1}{1 + {x}^{2}}
At time t=t,y=11+(x−vt)2t = t, y = \dfrac{1}{1 + ( x - vt{)}^{2}}
At t=1,y=11+(x−v)2…(i)t = 1, y = \dfrac{1}{1 + ( x - v{)}^{2}} \ldots ( i )
At t=1,y=11+(x−2)2…(ii)t = 1, y = \dfrac{1}{1 + ( x - 2{)}^{2}} \ldots ( ii )
Comparing (i)and(ii)( i ) and ( ii )
v=2ms−1v = 2m{s}^{- 1}
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