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JEE Main 202126 FebruaryEvening Shift
Exam
JEE Main
Year
2021
Date
26 February
Shift
Evening Shift
Subject
Physics
Chapter
Waves and Sound

JEE Main 2021 · 26 February · Evening Shift · Physics · Waves and Sound

A tuning fork A of unknown frequency produces 5beats s ^ - 1 with a...

A tuning fork AA of unknown frequency produces 5beatss−15beats{s}^{- 1} with a fork of known frequency 340Hz340Hz. When fork AA is filed, the beat frequency decreases to 2beatss−12beats{s}^{- 1}. What is the frequency of fork AA ?

Options

  1. A335Hz335Hz
  2. B338Hz338Hz
  3. C345Hz345Hz
  4. D342Hz342Hz

Correct answer

A. 335Hz335Hz

Step-by-step solution

Initially beat frequency =5Hz= 5Hz

so, ρA=340±5=345Hz,{ρ}_{A} = 340 \pm 5 = 345Hz, or 335Hz335Hz

after filing frequency increases slightly so, new value of frequency of A>ρAA > {ρ}_{A}

Now, beat frequency =2Hz= 2Hz

⇒⇒ new ρA=340±2=342Hz,{ρ}_{A} = 340 \pm 2 = 342Hz, or 338Hz338Hz

hence, original frequency of AA is ρA=335Hz{ρ}_{A} = 335Hz

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