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JEE Main 202126 FebruaryMorning Shift
Exam
JEE Main
Year
2021
Date
26 February
Shift
Morning Shift
Subject
Physics
Chapter
Waves and Sound

JEE Main 2021 · 26 February · Morning Shift · Physics · Waves and Sound

The mass per unit length of a uniform wire is 0 . 135g cm ^ - 1 . A...

The mass per unit length of a uniform wire is 0.135gcm−10 . 135g{cm}^{- 1}. A transverse wave of the form y=−0.21siny = - 0 . 21sin\left(x + 30t\right)isproducedinit,whereis produced in it, wherexisinmeterandis in meter andtisinsecond.Then,theexpectedvalueoftensioninthewireisis in second. Then, the expected value of tension in the wire isx \times {10}^{- 2}N.Valueof. Value ofx is (Round-off to the nearest integer)

Correct answer

0

Step-by-step solution

μ=0.135gmcm−1=0.0135kgm−1\mu = 0 . 135gm{cm}^{- 1} = 0 . 0135kg{m}^{- 1}

y=−0.21sin⁡(x+30t)y = - 0 . 21\sin \left(x + 30t\right)

(xx in meter & tt in sec)

v=ωk=301=30ms−1v = \dfrac{\omega}{k} = \dfrac{30}{1} = 30m{s}^{- 1}

v=Tμ⇒T=v2μ=(30)2(0.0135)v = \sqrt{\dfrac{T}{\mu}} ⇒ T = {v}^{2}\mu = {\left(30\right)}^{2}\left(0 . 0135\right)

=12.15= 12 . 15

=x×10−2N= x \times {10}^{- 2}N

⇒x=1215⇒ x = 1215

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