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JEE Main 201912 JanuaryEvening Shift
Exam
JEE Main
Year
2019
Date
12 January
Shift
Evening Shift
Subject
Physics
Chapter
Waves and Sound

JEE Main 2019 · 12 January · Evening Shift · Physics · Waves and Sound

A resonance tube is old and has a jagged end. It is still used in...

A resonance tube is old and has a jagged end. It is still used in the laboratory to determine the velocity of sound in air. A tuning fork of frequency 512Hz512Hz produces first resonance when the tube is filled with water to a mark 11cm11cm below a reference mark, near the open end of the tube. The experiment is repeated with another fork of frequency 256Hz256Hz which produces first resonance when water reaches a mark 27cm27cm below the reference mark. The velocity of sound in air, obtained in the experiment, is close to

Options

  1. A335ms−1335m{s}^{- 1}
  2. B341ms−1341m{s}^{- 1}
  3. C322ms−1322m{s}^{- 1}
  4. D328ms−1328m{s}^{- 1}

Correct answer

D. 328ms−1328m{s}^{- 1}

Step-by-step solution

λ14=11+e⇒v512×4=11+e...(1)\dfrac{{\lambda}_{1}}{4} = 11 + e ⇒ \dfrac{v}{512 \times 4} = 11 + e . . . ( 1 )

λ24=27+e⇒v256×4=27+e...(2)\dfrac{{\lambda}_{2}}{4} = 27 + e ⇒ \dfrac{v}{256 \times 4} = 27 + e . . . ( 2 )

Subtracting the equations,

v256×4×12=16cm=0.16m\dfrac{v}{256 \times 4} \times \dfrac{1}{2} = 16cm = 0 . 16m

⇒v=0.16×2×4×256⇒ v = 0.16 \times 2 \times 4 \times 256

=328ms−1= 328m{s}^{- 1}

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