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JEE Main 201912 JanuaryMorning Shift
Exam
JEE Main
Year
2019
Date
12 January
Shift
Morning Shift
Subject
Physics
Chapter
Waves and Sound

JEE Main 2019 · 12 January · Morning Shift · Physics · Waves and Sound

A travelling harmonic wave is represented by the equation y (x, t)...

A travelling harmonic wave is represented by the equation yy\left(x, t\right) = {10}^{- 3}sin(50t+2x),\left(50t + 2x\right)\text{,} where xx and yy are in meter and tt is in seconds. Which of the following is a correct statement about the wave?

Options

  1. AThe wave is propagating along the positive xx -axis with speed 25ms−125m{s}^{- 1}
  2. BThe wave is propagating along the positive xx -axis with speed 100ms−1100m{s}^{- 1}
  3. CThe wave is propagating along the negative xx -axis with speed 25ms−125m{s}^{- 1}
  4. DThe wave is propagating along the negative xx -axis with speed 100ms−1100m{s}^{- 1}

Correct answer

C. The wave is propagating along the negative xx -axis with speed 25ms−125m{s}^{- 1}

Step-by-step solution

Given wave equation, y(x,t)=10−3sin⁡(50t+2x)y\left(x, t\right) = {10}^{- 3}\sin \left(50t + 2x\right)

This equation is similar to the equation of wave travelling along the negative xx-axis which is given by

y(x,t)=Asin(\omegat+kx)y\left(x, t\right) = Asin\left(\omegat + kx\right)

After comparing, Angular frequency ω=50s−1\omega = 50{s}^{- 1}

Wave number k=2m−1k = 2{m}^{- 1}

The wave velocity, v=ωk=502=25ms−1v = \dfrac{\omega}{k} = \dfrac{50}{2} = 25m{s}^{- 1}

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