JEE Main201911 Jan 2019Morning ShiftPhysicsWaves and SoundActual
Equation of travelling wave on a stretched string of linear density 5 ~g / m is y =0.03 (450 t -9 x ) where distance and time are measured in SI units. The tension in the string is:
Options
- A10 ~N
- B7.5 ~N
- C12.5 ~N
- D5 ~N
Correct answer
C. 12.5 ~N
Step-by-step solution
We have given, y=0.03 (450 t-9 x) Comparing it with standard equation of wave, we get =450 k =9 v = k = 450 9 =50 ~m / s Velocity of travelling wave on a stretched string is given by v = T T =2500 = linear mass density T =2500 5 10⁻³ 12.5 ~N