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When two tuning forks (fork 1 and fork 2) are sounded simultaneously, 4 beats per second are heard. Now, some tape is attached on the prong of the fork 2 . When the tuning forks are sounded again, 6 beats per seconds are heard. If the frequency of fork 1 is 200 ~Hz , then what was the original frequency of fork 2 ?

Options

  1. A200 ~Hz
  2. B202 ~Hz
  3. C196 ~Hz
  4. D204 ~Hz

Correct answer

C. 196 ~Hz

Step-by-step solution

|f₁-f₂ |=4 Since mass of second tuning fork increases so f₂ decrease and beats increase so aligned & f₁>f₂ & f₂=f₁-4=196 aligned

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