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A string is stretched between fixed points separated by 75 ~cm . It is observed to have resonant frequencies of 420 ~Hz and 315 ~Hz . There are no other resonant frequencies between these two. Then, the lowest resonant frequency for this string is

Options

  1. A10.5 ~Hz
  2. B105 ~Hz
  3. C1.05 ~Hz
  4. D1050 ~Hz

Correct answer

B. 105 ~Hz

Step-by-step solution

n 2 ( v )=315, ( n +1) 2 v =420 Solving v 2 =105

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